Who would win in a fight? Muscular Girl or Giantess?

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  • #9708
    Tiny Black Guy
    Participant

    I forgot about that giantess calculator >.<

    I didnt weigh all the variables at the time, my bad.  Still a good debate though math leans torward giantess (height/weight/strength), but logic leans torwards muscle girl(conditioning/training/moves)…if that even possible  😕

    I shouldnt make polls when Im sleepy..I miss alot of little details. -_-

    #9709
    Anonymous
    Guest

    There's a seemingly unimortant part of info you've forgotten. To calculate the efficiency of a stike you don't use force, instead what you're looking at is momentum which is force multiplied by the lenght of the object applying strenght. Let's use a normal 6 foot girl for an example (no training, can anyone say magic) and make one several times stronger and the other twice as big. Since anyting over twice as big is beyond discussion since the increase in mass grows almost exponentially.

    The result is that the giantess would have an aproximative weight increase of 8 times while her hand is at least twice as long. Therfore making the momentum of her strike 8×2=16 times more powerfull than a strike from an average 6 feet tall girl.

    So assuming the muscle girl is 2 times heavier than average which is quite a lot…. she'd have to be eight times stronger than average to have a better momentum.

    If it's just a matter of comparing strenghts of a punch… then it's just a matter of defining everything with numbers… otherwise it's just a long and unprovable debate…..

    About the center of weight thing there's a very common mistake in movies and cartoons regarding this to confront mass you have to have mass as well so if you have a muscle girl that's 8 times as strong she'd have to be much heavier becuse not only would she kick her opponent away but she would kick herself away (it would be like a 0 Gravity fight).

    Oh and the bruce lee height fight thing is force versus tehnique…

    Noticed most people tand to say that the muscle girl should have fighting training because she is stronger…. that's a really biased oppinion, you're comparing their battle power not their battle provess….

    #9710
    Tiny Black Guy
    Participant

    There's a seemingly unimortant part of info you've forgotten. To calculate the efficiency of a stike you don't use force, instead what you're looking at is momentum which is force multiplied by the lenght of the object applying strenght. Let's use a normal 6 foot girl for an example (no training, can anyone say magic) and make one several times stronger and the other twice as big. Since anyting over twice as big is beyond discussion since the increase in mass grows almost exponentially.

    The result is that the giantess would have an aproximative weight increase of 8 times while her hand is at least twice as long. Therfore making the momentum of her strike 8×2=16 times more powerfull than a strike from an average 6 feet tall girl.

    So assuming the muscle girl is 2 times heavier than average which is quite a lot…. she'd have to be eight times stronger than average to have a better momentum.

    If it's just a matter of comparing strenghts of a punch… then it's just a matter of defining everything with numbers… otherwise it's just a long and unprovable debate…..

    About the center of weight thing there's a very common mistake in movies and cartoons regarding this to confront mass you have to have mass as well so if you have a muscle girl that's 8 times as strong she'd have to be much heavier becuse not only would she kick her opponent away but she would kick herself away (it would be like a 0 Gravity fight).

    Oh and the bruce lee height fight thing is force versus tehnique…

    Noticed most people tand to say that the muscle girl should have fighting training because she is stronger…. that's a really biased oppinion, you're comparing their battle power not their battle provess….

    point well taking, anyone wanna weigh in on this?  Wish I was smart enough too. >.

    #9711
    Axel3.14
    Participant

    Given their statistics, Id say the one with the lower center of gravity should win.

    #9712
    Tiny Black Guy
    Participant

    Given their statistics, Id say the one with the lower center of gravity should win.

    Intruiging proposal…anybody else have any opinions on this?

    #9713
    stmercy2020
    Participant

    As always, I weighs in late…

    I hate to have to vote the way I did (Giantess wins IMHO) because I really prefer buff girl stories to giantesses, but, as pointed out by a number of the scientifically inclined, assuming the only variables you're actually dealing with are weight training (the buff girl) vs. increased mass/reach (the giantess), then the physics of the battle pretty much imply that the giantess can't lose.

    Now there are a couple of things that could modify that.  First of all, anyone who spends a significant amount of time working out in the gym is going to have increased their pain tolerance fairly significantly- working out involves deliberately breaking down tissue so that your body can rebuild it stronger than before, after all, a process that involves at least a degree of pain.  Increased pain tolerance, endurance, and body awareness could, theoretically, all contribute to the buff girl's ability to stick it out longer in a fight and therefor win based on pure stamina.

    On the other hand, it's pretty unrealistic to think that somebody who looks like Jodi Ann Paterson has never set foot inside a gym or done any resistance training…  It takes more than just diet to maintain that sort of figure, after all.

    Oh, and about the whole center of gravity thing- that really only matters if buff girl can get close enough to apply leverage.  I had a match with a rassler who was about six inches shorter than me, the other day.  If I let him get close enough to hip toss me, it could get very dicey, especially since we both weighed in at around 200 pounds.  On the other hand, so long as I kept him at arms reach, used my legs to my advantage, I could deal with him quite effectively and there wasn't a whole heck of a lot he could do in return…

    Just my $0.02.

    #9714
    00tree
    Participant

    If you double someones height they weight should be somewhere around eight time the original number. Not only are you doubling the height but the person's dimensions should all be doubled as well. ( width AND depth ). Unless your just stretching the person to twice as tall.  ;D. my money is still on the muscle girl though. If your talking about someone who is fantastically tall vs. someone who if fantastically trained and muscular the person who knows there body better will usually be the winner unless one of the combatants is vastly stronger/faster/tougher. If you don't train you don't really know your limits.

    #9715
    Ad_Meyer
    Participant

    10 foot girl with 200 lbs is going to look positively anorexic.
    10 foot girl should weigh more like 800 lbs just to look 'Normal'
    (FYI, 10 foot girl with 800lbs should look like a 5 foot girl with
    100lbs weight, which is about normal build, doubled in all dimensions).

    So, as I can't imagine a 5 foot girl weighing 25lbs, I am positive
    that the buff girl would win this one. 

    #9716
    Lingster
    Keymaster

    Well, if you were doing the volume calculation for a cylinder, it would look like this:

    volume = ? x r² x height

    And for purposes of this, let's treat volume as mass because we're assuming a uniform density of consistent value both in our before and after numbers.

    So let's say the girl weighs 40kg and is 162 cm tall:

    40kg = avg. circumference x 162cm

    If we double that 162cm, we also have to double the radius that goes into her 'avg. circumference' value, which means to balance the equation we have to multiply 40kg times four.  So doubling the height of a 162cm girl to 324cm (10' 8") would require multiplying her mass/weight to 160kg (352.7 pounds).

    #9717
    Lingster
    Keymaster

    Wait – I made a mistake.  We'd need to square the old and new radii, not merely double it.  Hmmm.  This is a challenge.

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